Shell读取yaml文件
脚本
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21
| # function parse_yaml { local prefix=$2 local s='[[:space:]]*' w='[a-zA-Z0-9_]*' fs=$(echo @|tr @ '\034') sed -ne "s|^\($s\):|\1|" \ -e "s|^\($s\)\($w\)$s:$s[\"']\(.*\)[\"']$s\$|\1$fs\2$fs\3|p" \ -e "s|^\($s\)\($w\)$s:$s\(.*\)$s\$|\1$fs\2$fs\3|p" $1 | awk -F$fs '{ indent = length($1)/2; vname[indent] = $2; for (i in vname) {if (i > indent) {delete vname[i]}} if (length($3) > 0) { vn=""; for (i=0; i<indent; i++) {vn=(vn)(vname[i])("_")} printf("%s%s%s=\"%s\"\n", "'$prefix'",vn, $2, $3); } }' }
# # parse_yaml $1 $2
|
可以配合eval $(parse_yaml test.yaml)
将配置读出来
已知问题
该脚本无法读出下面的格式
1 2 3 4
| things: - first - second - third
|
参考文档
- http://stackoverflow.com/questions/5014632/how-can-i-parse-a-yaml-file-from-a-linux-shell-script